en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular Functions >

extreme f(x)=x^2+8x+16

Solution

extreme

Solution

Minimum (- 4, 0)

Solution steps

f^{'} (x) = 2 x + 8

Find intervals:

Decreasing

: - \infty < x < - 4,

Increasing

: - 4 < x < \infty

Plug

x = - 4

into

x^{2} + 8 x + 16 : 0

Minimum (- 4, 0)

Graph

Popular Examples

extreme f(x,y)=xy+4/x+2/y

extreme x^2-7x+7.7

extreme f(x)=2x+4

extreme f(x)=-cos(x)

extreme f(x)=x^2-3x-4

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+8x+16 ?
The extreme f(x)=x^2+8x+16 is Minimum(-4,0)