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inverse ofr x/(x+1)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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abscisses à l'origine log₂(2+x)−4

Solution

(14, 0)

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Solution steps

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(

1	2	3	4
5	6	7	8
3	2	3	2
3	1	7	8

)⁻¹

Inverse matrix

A matrix is invertible if and only if there is a sequence of elementary row (or column) operations taking it to the identity matrix.

Augmenter avec une matrice identité 4x4

[

1	2	3	4	∣	1	0	0	0
5	6	7	8	∣	0	1	0	0
3	2	3	2	∣	0	0	1	0
3	1	7	8	∣	0	0	0	1

]

Reduce the matrix on the left to the identity matrix

[

1	0	0	0	∣	−2512	1112	−56	13
0	1	0	0	∣	56	−16	13	−13
0	0	1	0	∣	3112	−1712	116	−13
0	0	0	1	∣	−1912	1112	−43	13

]

La matrice inverse est à droite de la matrice augmentée

−2512	1112	−56	13
56	−16	13	−13
3112	−1712	116	−13
−1912	1112	−43	13

)

Solve instead

domaine indéfini log₂(2+x)−4

gamme log₂(2+x)−4

inverser log₂(2+x)−4

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inverse ofr x/(x+1)

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