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derivative of (2x-5e^x)

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ddx ((2x−5)e^x)

Solution

2e^xx−3e^x

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ddx ((2x−5)e^x)

Apply the Product Rule: (f·g)′=f ′·g+f·g′

f=2x−5, g=e^x

=ddx (2x−5)e^x+ddx (e^x)(2x−5)

ddx (2x−5)=2

ddx (e^x)=e^x

=2e^x+e^x(2x−5)

Simplify 2e^x+e^x(2x−5): 2e^xx−3e^x

=2e^xx−3e^x

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

derivative of (2x-5e^x)

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