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domain ofe indéfini 2x+3

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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normale de y=4x²−6x, x=2

Solution

y=−110 x+215

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Trouver le point de tangente: (2, 4)

Calculer la pente de y=4x²−6x: 8x−6

Compute the slope at x=2: m=10

Calculer la pente de la droite perpendiculaire: m_p=−110

Trouver la droite de pente m=−110 et qui traverse (2, 4): y=−110 x+215

y=−110 x+215

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

domain ofe indéfini 2x+3

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