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inverse ofr laplace 2cos^3(x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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ddx (xln(x²+3))

Solution

ln(x²+3)+2x²x²+3

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ddx (xln(x²+3))

Appliquer la règle du produit: (f·g)′=f ′·g+f·g′

f=x, g=ln(x²+3)

=dxdx ln(x²+3)+ddx (ln(x²+3))x

dxdx =1

ddx (ln(x²+3))=2xx²+3

=1· ln(x²+3)+2xx²+3 x

Simplifier 1· ln(x²+3)+2xx²+3 x: ln(x²+3)+2x²x²+3

=ln(x²+3)+2x²x²+3

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inverse ofr laplace 2cos^3(x)

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