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improper fraction 8 1/5

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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x²−x−6=0

Solution

x=3, x=−2

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Résoudre par la formule quadratique

Résoudre en complétant le carré

Résoudre en factorisant

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x²−x−6=0

Résoudre par la formule quadratique

x_{1, 2}=−(−1)± √(−1)²−4· 1· (−6)2· 1

√(−1)²−4· 1· (−6)=5

x_{1, 2}=−(−1)± 52· 1

Séparer les solutions

x₁=−(−1)+52· 1 , x₂=−(−1)−52· 1

x=−(−1)+52· 1 : 3

x=−(−1)−52· 1 : −2

Les solutions de l'équation de forme quadratique sont :

x=3, x=−2

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

improper fraction 8 1/5

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