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derivative of e^xcos(x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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ddx (6x¹⁷+14x−614x−15 )

Solution

1344x¹⁷−1530x¹⁶−126(14x−15)²

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ddx (6x¹⁷+14x−614x−15 )

Appliquer la règle du quotient: (fg )^′=f ′·g−g′·fg²

=ddx (6x¹⁷+14x−6)(14x−15)−ddx (14x−15)(6x¹⁷+14x−6)(14x−15)²

ddx (6x¹⁷+14x−6)=102x¹⁶+14

ddx (14x−15)=14

=(102x¹⁶+14)(14x−15)−14(6x¹⁷+14x−6)(14x−15)²

Développer (102x¹⁶+14)(14x−15)−14(6x¹⁷+14x−6): 1344x¹⁷−1530x¹⁶−126

=1344x¹⁷−1530x¹⁶−126(14x−15)²

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

derivative of e^xcos(x)

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