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1/5+1/5

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

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log_□

θ

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∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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asymptotes y=xx²−6x+8

Solution

Vertical: x=2, x=4, Horizontal: y=0

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Définition de l'amplitude

Pour f(x)=A\cdot\sin(Bx-C)+D l'amplitude est|A|

f(x)=2sin(5x), A=2
Par conséquent, l'amplitude |A| est 2

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domaine indéfini xx²−6x+8

gamme xx²−6x+8

inverser xx²−6x+8

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

1/5+1/5

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