periodicity of cos(2x+5)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

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∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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ddx (x²x²+3 )

Solution

6x(x²+3)²

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Solution steps

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ddx (x²x²+3 )

Appliquer la règle du quotient: (fg )^′=f ′·g−g′·fg²

=ddx (x²)(x²+3)−ddx (x²+3)x²(x²+3)²

ddx (x²)=2x

ddx (x²+3)=2x

=2x(x²+3)−2xx²(x²+3)²

Simplifier 2x(x²+3)−2xx²(x²+3)² : 6x(x²+3)²

=6x(x²+3)²

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Notebook

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

`x`²	`x`<−2
ln(`x`+5)	`x`≥−2

sin(`x`)	`x`<0
2`x`	`x`≥0

√`x`+2	`x`<1
`xx`²−6`x`+8	`x`≥1

√`x`²−4	`x`<0
`x`³−`x`	`x`≥0

periodicity of cos(2x+5)

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