inverse ofr x/(x+1)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for partial fractions long division line

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Steps Examples

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gamme 2sec(x)

Solution

f(x)≤ −2 or f(x)≥ 2

Interval Notation

(−∞ , −2]∪ [2, ∞ )

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Solution steps

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Définition de la plage de fonction

L'ensemble des valeurs de la variable dépendante pour lesquelles une fonction est définie

La plage de la base de la fonction sec est sec(x)≤ −1 or sec(x)≥ 1

sec(x)≤ −1 or sec(x)≥ 1

Multiplier les bornes de la plage par : 2

2sec(x)≤ −2 or 2sec(x)≥ 2

Par conséquent la plage est

f(x)≤ −2 or f(x)≥ 2

Solve instead

domaine indéfini 2sec(x)

périodicité 2sec(x)

amplitude 2sec(x)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

inverse ofr x/(x+1)

Solution

Solution steps

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