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derivative of tan^5(x)

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∫ 4x−7x²+5x dx

Solution

−75 ln|x|+275 ln|x+5|+C

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(

3	1	1
1	3	−1
2	4	1

)

Valeurs propres d'une matrice

Soit A une matrice carrée, η un vecteur et λ un scalaire qui répond à Aη=λη,
alors λ iest appelée la valeur propre associée avec le vecteur propre η de A

Les valeurs propres de A sont les racines de l'équation caractéristique det(A−λ I)=0

det((

3	1	1
1	3	−1
2	4	1

)−λ(

1	0	0
0	1	0
0	0	1

)): −λ³+7λ²−16λ+16

Résoudre −λ³+7λ²−16λ+16=0: λ=4, λ=32 +i√72 , λ=32 −i√72

Les valeurs propres sont :

λ=4, λ=32 +i√72 , λ=32 −i√72

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

derivative of tan^5(x)

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