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facteur completely 4x^2-10

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foyers 4x²−9y²−48x−72y+108=0

Solution

(6, −4+√39), (6, −4−√39)

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Foyers d'une hyperbole

Pour une hyperbole tournée de haut en bas, les foyers (points de focalisation) sont définis par (h, k+c), (h, k−c),
où c=√a²+b² est la distance du centre (h, k) vers un foyer

(h, k+c), (h, k−c)

Calculer les propriétés d'une hyperbole

4x²−9y²−48x−72y+108=0: Hyperbole de haut en bas avec (h, k)=(6, −4), a=2√3, b=3√3

(6, −4+c), (6, −4−c)

Calculer c :

c=√(2√3)²+(3√3)²: √39

(6, −4+√39), (6, −4−√39)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

facteur completely 4x^2-10

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