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integral of (x^2+1)/(x^5)

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foyers x²+(y+3)²=16

Solution

(0, −3), (0, −3)

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Foyers de l'ellipse

Pour une ellipse avec un axe majeur parallèle à l'axe des x, les foyers (points de focalisation) sont définis par (h, k+c), (h, k−c),
où c=√b²−a² est la distance du centre (h, k) vers un foyer

(h, k+c), (h, k−c)

Calculer les propriétés d'une ellipse

x²+(y+3)²=16: Ellipse de centre (h, k)=(0, −3), b=4, a=4

(0, −3+c), (0, −3−c)

Calculer c :

c=√4²−4²: 0

(0, −3+0), (0, −3−0)

Redéfinir

(0, −3), (0, −3)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

integral of (x^2+1)/(x^5)

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