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integral of-x^{12}-2x^2-1

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∫ −x¹²−2x²−1dx

Solution

−x¹³13 −2x³3 −x+C

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∫ −x¹²−2x²−1dx

Apply the Sum Rule: ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx

=−∫ x¹²dx−∫ 2x²dx−∫ 1dx

∫ x¹²dx=x¹³13

∫ 2x²dx=2x³3

∫ 1dx=x

=−x¹³13 −2x³3 −x

Add a constant to the solution

=−x¹³13 −2x³3 −x+C

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

integral of-x^{12}-2x^2-1

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