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domain ofe indéfini 3x

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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centre (x−2)²+(y−3)²=16

Solution

(2, 3)

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(x−2)²+(y−3)²=16

Equation d'un cercle

(x−a)²+(y−b)²=r² iest l'équation du cercle de rayon r, centrée en (a, b)

Récrire (x−2)²+(y−3)²=16 sous la forme de l'équation standard du cercle

(x−2)²+(y−3)²=4²

Par conséquent les propriétés du cercle sont :

(a, b)=(2, 3), r=4

Et le centre est :

(2, 3)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

domain ofe indéfini 3x

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