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slope of tangent f(x)=sin(2x), x=(pi)/2

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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slope of tangent f(x)=sin(2x), x=π2

Solution

−2

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The slope of the tangent at a point is the derivative of the function at this point

ddx (sin(2x))=cos(2x)· 2

Find the value of cos(2x)· 2 for x=π2 : −2

−2

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slope of tangent f(x)=sin(2x), x=(pi)/2

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