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inverser laplace 2x2x2−x
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Solution
2δ(t)+2et
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Solution steps
Solve by:
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L−1{2x2x2−x}
Prendre la fraction partielle de 2x2x2−x:2+2x−1
=L−1{2+2x−1}
Utiliser la propriété linéaire de la transformée inverse de Laplace : Pour les fonctions f(s),g(s) et les constantes a,b:L−1{a·f(s)+b·g(s)}=a·L−1{f(s)}+b·L−1{g(s)}