domain ofe indéfini (x^2+1)(x^2-1)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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gamme 2x²+6x

Solution

f(x)≤ −4√3 or f(x)≥ 4√3

Interval Notation

(−∞ , −4√3]∪ [4√3, ∞ )

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Définition de la plage de fonction

L'ensemble des valeurs de la variable dépendante pour lesquelles une fonction est définie

Récrire comme

2x²+6x =y

Multiplier les deux côtés par x

2x²+6=yx

La plage est l'ensemble des y pour lesquels le discriminant est supérieur ou égal à zéro

Discriminant noté 2x²+6=yx: y²−48

y²−48≥ 0 : y≤ −4√3 or y≥ 4√3

Vérifier si les points d'extrémités de la plage d'intervalle sont inclus

y=−4√3 : Inclus

y=4√3 : Inclus

Par conséquent la plage est

f(x)≤ −4√3 or f(x)≥ 4√3

Solve instead

domaine indéfini 2x²+6x

inverser 2x²+6x

points d'intersection 2x²+6x

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

domain ofe indéfini (x^2+1)(x^2-1)

Solution

Solution steps

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