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simplifier 613+511
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Solution
131143
+1
Decimal
0.91608…
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Solution steps
Solve by:
One step at a time
L−1{x−1x+1}
Prendre la fraction partielle de x−1x+1:1−2x+1
=L−1{1−2x+1}
Utiliser la propriété linéaire de la transformée inverse de Laplace : Pour les fonctions f(s),g(s) et les constantes a,b:L−1{a·f(s)+b·g(s)}=a·L−1{f(s)}+b·L−1{g(s)}