sommets (5x)^2

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for expand factor rationalize

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gamme 2x+1

Solution

−∞ <f(x)<∞

Interval Notation

(−∞ , ∞ )

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Solution steps

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ddx (ln(x¹⁷+14x))

Appliquer la règle de la chaine: 1x¹⁷+14x ddx (x¹⁷+14x)

=1x¹⁷+14x ddx (x¹⁷+14x)

ddx (x¹⁷+14x)=17x¹⁶+14

=1x¹⁷+14x (17x¹⁶+14)

Simplifier 1x¹⁷+14x (17x¹⁶+14): 17x¹⁶+14x¹⁷+14x

=17x¹⁶+14x¹⁷+14x

Solve instead

points d'intersection 2x+1

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domaine indéfini 2x+1

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

sommets (5x)^2

Solution

Solution steps

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