gamme 9-x^2

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for expand factor rationalize

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inverser (

−4	−17
2	2

)

Solution

(

113	1726
−113	−213

)

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Solution steps

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L⁻¹{2x³−2x²+1x²−x }

Prendre la fraction partielle de 2x³−2x²+1x²−x : 2x−1x +1x−1

=L⁻¹{2x−1x +1x−1 }

Utiliser la propriété linéaire de la transformée inverse de Laplace :
Pour les fonctions f(s), g(s) et les constantes a, b: L⁻¹{a·f(s)+b·g(s)}=a·L⁻¹{f(s)}+b·L⁻¹{g(s)}

=2L⁻¹{x}−L⁻¹{1x }+L⁻¹{1x−1 }

L⁻¹{x}: δ′ (t)

L⁻¹{1x }: H(t)

L⁻¹{1x−1 }: e^t

=2δ′ (t)−H(t)+e^t

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

gamme 9-x^2

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