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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

Solutions > Prove That Calculator >

domain ofe indéfini (x^2+x+1)/x

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

π

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for expand factor rationalize

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Steps Examples

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naclaurin sin(x)

Solution

∑_n=0^∞(−1)ⁿx²ⁿ⁺¹(2n+1)!

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Les séries de Maclaurin

La série de Taylor d'une fonction f(x) en a est définie comme :
f(x)=f(a)+f^′(a)1! (x−a)+f^′′(a)2! (x−a)²+f^′′′(a)3! (x−a)³+…

La série de Maclaurin d'une fonction f(x) est une série de Taylor de la fonction f(x) en : a=0
f(x)=f(0)+f^′(0)1! (x)+f^′′(0)2! (x)²+f^′′′(0)3! (x)³+…

Appliquer la formule de Maclaurin

=0+ddx (sin(x))(0)1! x+d²dx² (sin(x))(0)2! x²+d³dx³ (sin(x))(0)3! x³+…

Evaluer des dérivées

=0+11! x+02! x²+−13! x³+04! x⁴+15! x⁵+06! x⁶+−17! x⁷+08! x⁸+19! x⁹+…

Redéfinir

=11! x−13! x³+15! x⁵−17! x⁷+19! x⁹+…

Représentation de la somme des séries

=∑_n=0^∞(−1)ⁿx²ⁿ⁺¹(2n+1)!

Prove That Examples

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