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next term a_{n+1}=-3a_{n},a_{1}=8

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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développer (x²+3y)³

Solution

x⁶+9x⁴y+27x²y²+27y³

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(x²+3y)³

Appliquer la formule du cube parfait: (a+b)³=a³+3a²b+3ab²+b³

(x²+3y)³=(x²)³+3(x²)²· 3y+3x²(3y)²+(3y)³

=(x²)³+3(x²)²· 3y+3x²(3y)²+(3y)³

Simplifier (x²)³+3(x²)²· 3y+3x²(3y)²+(3y)³: x⁶+9x⁴y+27x²y²+27y³

=x⁶+9x⁴y+27x²y²+27y³

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

next term a_{n+1}=-3a_{n},a_{1}=8

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