axe y=(-3x^2-2x+6)/5

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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Steps Examples

Generated by AI

angle (1, 1)

Solution

π4

Degrees

45^◦

Decimal

0.78539…

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Solution steps

One step at a time

L'angle depuis l'axe des x

L'angle entre un vecteur, (

a

b

) et l′axe positif des x dépend du quadrant sur lequel se trouve le point dans
Premier quadrant : θ=arctan(ba )
Deuxième quadrant : θ=π−arctan(|ba |)
Troisième quadrant : θ=arctan(|ba |)−π
Quatrième quadrant : θ=−arctan(|ba |)

Le quadrant de (1, 1): 1

L'angle entre (1, 1) et l'axe des x est

arctan(11 )

Calculer arctan(θ): arctan(11 )=π4

=π4

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

axe y=(-3x^2-2x+6)/5

Solution

Solution steps

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